/Python/Sorting values in dictionary in python

Sorting values in dictionary in python

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sorting values in dictionary in python

#instead of using python inbuilt function we can it compute directly.
#here iam sorting the values in descending order..
d = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
s=[]
for i in d.items():
  s.append(i)
for i in range(0,len(s)):
  for j in range(i+1,len(s)):
    if s[i][1]<s[j][1]:
      s[i],s[j]=s[j],s[i]
print(dict(s))

Similar codes

2 votes293 views3 answers
Local variable
Python
0 vote286 views1 answer
Python upgrade pip scipy
Python
1 vote315 views1 answer
Get all classes from css file using python
Python
0 vote272 views1 answer
Dataframe passed by reference or value
Python
1 vote295 views2 answers
Run flask app windows
Python
1 vote322 views1 answer
Size of variable python
Python
0 vote283 views1 answer
File "pandas/_libs/index.pyx", line 465, in pandas._libs.index.DatetimeEngine.get_loc KeyError: Timestamp('2019-01-02 07:09:00')
Python
2 votes307 views1 answer
Click js selenium python
Python
0 vote309 views1 answer
Python replace null in list
Python
0 vote314 views1 answer
The following packages have unmet dependencies: libnode72 : Conflicts: nodejs-legacy E: Broken packages
Python