/Python/Python unknow number of arguments, default argument,

Python unknow number of arguments, default argument,

def foo(a, b=3, *args, **kwargs):
  defaultKwargs = { 'c': 10, 'd': 12 }
  kwargs = { **defaultKwargs, **kwargs }
  print(a, b, args, kwargs)
  
  # Do something    

foo(1) # 1 3 () {'c': 10, 'd': 12}
foo(1, d=5) # 1 3 () {'c': 10, 'd': 5}
foo(1, 2, 4, d=5) # 1 2 (4,) {'c': 10, 'd': 5}

Source: stackoverflow.com

Similar codes

10 votes295 views2 answers
Django import settings
Python
0 vote253 views1 answer
2d list input in python
Python
-1 vote283 views1 answer
Add border to table in python pptx
Python
0 vote319 views1 answer
Bfs in python 3
Python
0 vote281 views1 answer
How to save brake lines on textarea in django
Python
0 vote291 views1 answer
Python how to make boxplots with swarmplot
Python
6 votes315 views1 answer
Python soap
Python
0 vote283 views1 answer
Maior valor lista python
Python
0 vote367 views1 answer
Encanto meaning spanish
Python
0 vote300 views1 answer
Remove specific character from object in pandas column using iloc
Python