/Python/Python unknow number of arguments, default argument,

Python unknow number of arguments, default argument,

def foo(a, b=3, *args, **kwargs):
  defaultKwargs = { 'c': 10, 'd': 12 }
  kwargs = { **defaultKwargs, **kwargs }
  print(a, b, args, kwargs)
  
  # Do something    

foo(1) # 1 3 () {'c': 10, 'd': 12}
foo(1, d=5) # 1 3 () {'c': 10, 'd': 5}
foo(1, 2, 4, d=5) # 1 2 (4,) {'c': 10, 'd': 5}

Source: stackoverflow.com

Similar codes

0 vote231 views1 answer
Get next multiple of a number
Python
31 votes216 views5 answers
Python day from date
Python
25 votes244 views4 answers
Pandas count the number of unique values in a column
Python
0 vote250 views1 answer
Python inject into process
Python
0 vote242 views1 answer
Western school district
Python
0 vote243 views1 answer
Django trim string whitespace
Python Django
0 vote236 views1 answer
Get_scholarly_instance()
Python
0 vote231 views1 answer
Python terminate program after specific time
Python
4 votes220 views2 answers
How to use ternary operater in python
Python
3 votes250 views2 answers
How to check if python is installed on mac
Python