Python sorted lambda

Python lambda key sort

>>> student_tuples = [
...     ('john', 'A', 15),
...     ('jane', 'B', 12),
...     ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2])    # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]

Source: docs.python.org

Sorted python lambda

lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)

Source: stackoverflow.com

Python sorted lambda

a = ["tim", "bob", "anna", "steve", "john"]

# sorts the list by the first letter of each name
b = sorted(a, key=lambda x : x[0])
# x = each of the values in the list a

# sorts the list by length FIRST, then alphabetical order SECOND
c = sorted(a, key=lambda x : (len(x), x))

Python sort multiple keys

records.sort(
  key = lambda l: (l[0], l[2])
)

Source: lleess.com

Sorted lambda

sorted(student_tuples, key=lambda student: student[2])

Similar codes

53 votes255 views3 answers
Abc list python
Python
0 vote203 views1 answer
Replace hour , minute, seconds in timestamp pandas
Python
3 votes267 views1 answer
Pyautogui moveTo overtime
Python
1 vote243 views1 answer
How to change size of xticks
Python
0 vote236 views2 answers
Python convert string to list of dictionaries
Python
2 votes262 views1 answer
Get median of column pandas
Python
0 vote231 views1 answer
Correlation between images python
Python
4 votes253 views1 answer
How to make a custom icon for pygame
Python
0 vote248 views1 answer
Python input timeout
Python
0 vote240 views1 answer
Python string: .join()
Python