/SQL/Coderbyte mysql challenge MySQL challenge, your query should return the informatioi for the employee with the third highest salary.

Coderbyte mysql challenge MySQL challenge, your query should return the informatioi for the employee with the third highest salary.

Sql find second highest salary employee

/* sql 2nd highest salary employee */
select sal, ename
from emp
where sal =
    (
        select max(sal) from emp where sal <
            (select max(sal) from emp)
    )
----------------------------------------------- option 2
select *
from 
(
    select ename, sal, dense_rank() over(order by sal desc) rank
    from emp
)
where rank =2;

Coderbyte mysql challenge MySQL challenge, your query should return the informatioi for the employee with the third highest salary.

In this MySQL challenge, your query should return the information for the employee with the third highest salary. Write a query that will find this employee and return that row, but then replace the DivisionID column with the corresponding DivisionName from the table cb_companydivisions. You should also replace the ManagerID column with the ManagerName if the ID exists in the table and is not NULL.

Your output should look like the following table.

Coderbyte mysql challenge MySQL challenge, your query should return the informatioi for the employee with the third highest salary.

select *
from 
(
    select ename, sal, dense_rank() over(order by sal desc) rank
    from emp
)
where rank =3;

Similar codes

1 vote367 views1 answer
Random name function in mysql for nvarchar
SQL
0 vote362 views1 answer
Mysql exception output
SQL
-1 vote336 views1 answer
Django.core.exceptions.ImproperlyConfigured: mysqlclient 1.3.13 or newer is required; you have 0.8.0.
SQL
8 votes453 views1 answer
Mysql dump restore
SQL
0 vote343 views2 answers
Mysql select date from datetime
SQL
1 vote363 views1 answer
Create new index takes long time postgresql
SQL
0 vote349 views1 answer
How to put 0 or 000 depending IDCustomer length in sql server
SQL
5 votes342 views3 answers
String concatenation sql server
SQL
1 vote356 views1 answer
Operator does not exist: integer = text
SQL
1 vote364 views1 answer
Oracle sequence last_number
SQL