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Python count appearances in list

Python find number of occurrences in list

student_grades = [9.1, 8.8, 10.0, 7.7, 6.8, 8.0, 10.0, 8.1, 10.0, 9.9]

samebnumber = student_grades.count(10.0)

print(samebnumber)

Python count repeated elements in a list

# Basic syntax:
dict_of_counts = {item:your_list.count(item) for item in your_list}

# Example usage:
your_list = ["a", "b", "a", "c", "c", "a", "c"]
dict_of_counts = {item:your_list.count(item) for item in your_list}
print(dict_of_counts)
--> {'a': 3, 'b': 1, 'c': 3}

Source: stackoverflow.com

Python count appearances in list

a = [1,2,2,2,1]
a.count(2)

Python count appearances in list

your_list = ["a", "b", "a", "c", "c", "a", "c"]
d= {}
for items in your_list:
    d[items] = your_list.count(items)
print(d)

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