/Python/Numpy array divide each row by its sum

Numpy array divide each row by its sum

>>> e
array([[ 0.,  1.],
       [ 2.,  4.],
       [ 1.,  5.]])
# Method #1
>>> e/e.sum(axis=1)[:,None]
array([[ 0.        ,  1.        ],
       [ 0.33333333,  0.66666667],
       [ 0.16666667,  0.83333333]])

# Method #2
>>> (e.T/e.sum(axis=1)).T
array([[ 0.        ,  1.        ],
       [ 0.33333333,  0.66666667],
       [ 0.16666667,  0.83333333]])

# Method #3:
>>> e/e.sum(axis=1, keepdims=True)
array([[ 0.        ,  1.        ],
       [ 0.33333333,  0.66666667],
       [ 0.16666667,  0.83333333]])

Source: stackoverflow.com

Similar codes

0 vote268 views2 answers
Cv2 frame size
Python
-1 vote251 views1 answer
Pip path windows 10
Python
1 vote271 views3 answers
Isprime in python
Python
2 votes285 views2 answers
Convert generator to list python
Python
0 vote234 views1 answer
Python concatenate dictionaries
Python
1 vote282 views1 answer
Python array append extend
Python
4 votes279 views1 answer
Delete element of a list from another list python
Python
0 vote282 views1 answer
Python missing characters hackerrank solution
Python
0 vote286 views1 answer
Black code formatter
Python
1 vote301 views1 answer
Choose random file from directory
Python