/PHP/Mysqli_query() expects parameter 1 to be mysqli, string given

Mysqli_query() expects parameter 1 to be mysqli, string given

Mysqli_select_db expects 2 parameters

//do the correction as below:

$conn = mysqli_connect('localhost', 'root', '');
//the first thing that you have to pass connection variable in the select_db as first parameter. as below.

mysqli_select_db($conn,'altislife-dev');
//also you have to pass connection variable in mysqli_query() as first parameter as given below.

$records=mysqli_query($conn,$sql);

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, string given in

mysqli_fetch_array($result)

Source: stackoverflow.com

Mysqli_query() expects parameter 1 to be mysqli, string given

<?

$qry = mysqli_query($connection, $query);
// $connection: database connection
// $query: your query

Mysqli_fetch_array() expects parameter 1 to be mysqli_result

$sql = "select * from privinsi";$result = mysqli_query($connection,$sql);while($r = mysqli_fetch_array($result) 
){  // your code here}

-1

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