How to sort a list in python

Python sort list in reverse

#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)

How to sort a list descending python

# defning A as a list
A.sort(reverse = True)

Sort list python

>>> a = [5, 2, 3, 1, 4]
>>> a.sort()
>>> a
[1, 2, 3, 4, 5]

Source: docs.python.org

Sort a list of array python

from operator import itemgetter
A = [[10, 8], [90, 2], [45, 6]]
print("Sorted List A based on index 0: % s" % (sorted(A, key=itemgetter(0))))
B = [[50, 'Yes'], [20, 'No'], [100, 'Maybe']]
print("Sorted List B based on index 1: % s" % (sorted(B, key=itemgetter(1))))

"""
Output:
Sorted List A based on index 0: [[10, 8], [45, 6], [90, 2]]
Sorted List B based on index 1: [[100, 'Maybe'], [20, 'No'], [50, 'Yes']]
"""

Source: delftstack.com

Python sort list

# example list, product name and prices
price_data = [['product 1', 320.0],
             ['product 2', 4387.0],
             ['product 3', 2491.0]]

# sort by price
print(sorted(price_data, key=lambda price: price[1]))

How to sort a list in python

l=[1,3,2,5]
l= sorted(l)
print(l)
#output=[1, 2, 3, 5]
#or reverse the order:
l=[1,3,2,5]
l= sorted(l,reverse=True)
print(l)
#output=[5, 3, 2, 1]

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