/Python/Sort list of dictionaries python

Sort list of dictionaries python

Sort list of dictionaries by key python

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

Sorting a dictionary in python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Source: stackoverflow.com

Sort list of dictionaries python

unsorted_list = [{"key1":5, "key2":2}, {"key1":5, "key2":1}]
sorted_list = sorted(unsorted_list, key=lambda k: k["key2"])

Sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

How to sort a dictionary py

orders = {
	'cappuccino': 54,
	'latte': 56,
	'espresso': 72,
	'americano': 48,
	'cortado': 41
}

sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)

for i in sort_orders:
	print(i[0], i[1])

Source: careerkarma.com

Similar codes

0 vote165 views1 answer
IndexError: tuple index out of range
Python
31 votes161 views6 answers
Try except
Python
0 vote161 views1 answer
Get random superhero images
Python
0 vote175 views1 answer
Sort a set in python
Python
13 votes166 views2 answers
How to get last letter of string python
Python
0 vote163 views1 answer
Python if not explaned
Python
1 vote168 views1 answer
Split data train, test by id python
Python
1 vote152 views1 answer
Convert pandas dataframe to django queryset
Python
1 vote182 views2 answers
AttributeError: module 'yaml' has no attribute 'load_all'
Python
1 vote178 views1 answer
Sha256 pandas
Python