/Python/Python - sort dictionary by value

Python - sort dictionary by value

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary by values

from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)

Source: thomas-cokelaer.info

Similar codes

1 vote245 views1 answer
Django queryset multiple filters
Python Django
2 votes198 views1 answer
How to check if all characters in string are same python
Python
2 votes229 views1 answer
User input of int type in python
Python
1 vote216 views1 answer
Example XlsxWriter in Python
Python
2 votes207 views2 answers
Pypi
Python
4 votes228 views2 answers
Primary key django model
Python Django
0 vote220 views1 answer
Dataframe select row by index value
Python
10 votes208 views4 answers
Python filename without extension
Python
0 vote232 views1 answer
Python float to string n decimals
Python
1 vote219 views1 answer
How to set bgcolor of a widget in pyqt5
Python