/Python/Python - sort dictionary by value

Python - sort dictionary by value

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary by values

from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)

Source: thomas-cokelaer.info

Similar codes

10 votes318 views4 answers
Pandas
Python
0 vote324 views1 answer
How to plot a linear equation in matplotlib
Python
0 vote312 views1 answer
Find occerences in list python
Python
-1 vote313 views1 answer
How to join two dataframe in pandas based on two column
Python
17 votes311 views3 answers
Python ModuleNotFoundError: No module named '_tkinter'
Python
-2 votes346 views2 answers
Python program to find n prime numbers
Python
5 votes321 views2 answers
Beautifulsoup find by class
Python
6 votes375 views2 answers
Python cd to file
Python
0 vote313 views1 answer
Tkinter simple notification
Python
0 vote337 views1 answer
Fcn tensorflow
Python