Find the Missing Number

#include <bits/stdc++.h>
using namespace std;
 
// Function to get the missing number
int getMissingNo(int a[], int n)
{
 
    int total = (n + 1) * (n + 2) / 2;
    for (int i = 0; i < n; i++)
        total -= a[i];
    return total;
}
 
// Driver Code
int main()
{
    int arr[] = { 1, 2, 4, 5, 6 };
    int n = sizeof(arr) / sizeof(arr[0]);
    int miss = getMissingNo(arr, n);
    cout << miss;
}

Source: geeksforgeeks.org

Missing number

numbers = input("Enter your numbers with ','separated form : ")
int_array = list(map(int,numbers.split(",")))
Sum = 0
for i in range(len(int_array)):
    Sum = Sum+int_array[i]
n = len(int_array) +1
missing = (((n+1) * (n))/2) -Sum 
print(missing)

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