Python dict order a dict by key

Sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Python dict order a dict by key

d1 = dict(sorted(d.items(), key = lambda x:x[0]))

Source: stackoverflow.com

Similar codes

0 vote206 views1 answer
Python - How To Check if a String Is a Palindrome
Python
9 votes218 views2 answers
Make string numeric pandas
Python
9 votes202 views1 answer
Delete object from table django
Python Django
0 vote202 views3 answers
How to print a text in python
Python
0 vote212 views1 answer
Write int in file python
Python
0 vote254 views1 answer
Pandas each row?
Python
0 vote194 views1 answer
Scikit learn tree
Python
0 vote196 views1 answer
Array destructuring python
Python
1 vote243 views1 answer
Keep the user logged in even though user changes password django
Python Django
0 vote199 views1 answer
Weight constraints keras cnn
Python