Python dict order a dict by key

Sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Python dict order a dict by key

d1 = dict(sorted(d.items(), key = lambda x:x[0]))

Source: stackoverflow.com

Similar codes

33 votes287 views3 answers
How to convert a byte array to string in python
Python
0 vote236 views1 answer
Msg91 python
Python
0 vote264 views1 answer
Lineplot in plt
Python
0 vote245 views1 answer
Isosceles triangle code in python
Python
0 vote232 views1 answer
If list is null python apply any function site:stackoverflow.com
Python
0 vote199 views1 answer
Django rest framework multiple user registration
Python Django
0 vote234 views1 answer
Ssl django nginx
Python
20 votes258 views4 answers
Button tkinter
Python
1 vote240 views1 answer
Python retry
Python
0 vote230 views1 answer
Lamda in f string
Python