/Shell/Bash/Sed use match in replacement

Sed use match in replacement

For using match in sed replacement, just border it with '\(' and '\)':
echo Before123 | sed 's/Before\([0-9]*\)/\1After/g'
123After	# number is matched withtin '\( \)' and replaced in '\1'
Example with 2 match replacements
echo a_b | sed 's/\(^.*\)_\(.*$\)/first is \1 and \2 is after/g'

Similar codes

0 vote190 views1 answer
Install teams linux
Shell/Bash
0 vote181 views1 answer
Ignore Composer Platform Request
Shell/Bash
0 vote181 views1 answer
MultipleObjectsReturned: get() returned more than one Question -- it returned 3!
Shell/Bash
-2 votes190 views2 answers
How to run exe file in linux
Shell/Bash
5 votes192 views2 answers
Bitnami restart apache
Shell/Bash
-1 vote192 views2 answers
Create jar with maven commandline
Shell/Bash
2 votes172 views1 answer
Check changes after git pull
Shell/Bash
0 vote180 views1 answer
Add bash as defult on arch
Shell/Bash
0 vote173 views1 answer
Host gitlab on private instance
Shell/Bash
1 vote190 views1 answer
Ubuntu download yasm
Shell/Bash