/Python/How to stop a program after 1 second in python

How to stop a program after 1 second in python

import multiprocessing
import time

# Your foo function
def foo(n):
    for i in range(10000 * n):
        print "Tick"
        time.sleep(1)

if __name__ == '__main__':
    # Start foo as a process
    p = multiprocessing.Process(target=foo, name="Foo", args=(10,))
    p.start()

    # Wait 10 seconds for foo
    time.sleep(10)

    # Terminate foo
    p.terminate()

    # Cleanup
    p.join()

Source: stackoverflow.com

Similar codes

12 votes324 views5 answers
Django-cors-headers
Python
0 vote296 views1 answer
Reverse relationship in django for one to one field for usage in Django rest serializer
Python Django
0 vote303 views1 answer
Staff user is not restricting permission in django
Python Django
0 vote278 views1 answer
Pandas filter dataframe if an elemnt is in alist
Python
0 vote277 views1 answer
Pytest temp directory
Python
0 vote299 views1 answer
RuntimeError: Please use tf.experimental.tensorrt.Converter in TF 2.0. site:stackoverflow.com
Python
2 votes273 views1 answer
Tkinter info box
Python
3 votes326 views1 answer
Disable csrf for one url django
Python Django
0 vote261 views2 answers
Rotatelist in python
Python
2 votes275 views2 answers
How to convert csv into list
Python