/Python/Efficiently count zero elements in numpy array?

Efficiently count zero elements in numpy array?

In [3]: arr
Out[3]: 
array([[1, 2, 0, 3],
      [3, 9, 0, 4]])

In [4]: np.count_nonzero(arr==0)
Out[4]: 2

In [5]:def func_cnt():
            for arr in arrs:
                zero_els = np.count_nonzero(arr==0)
                # here, it counts the frequency of zeroes actually

Source: stackoverflow.com

Similar codes

0 vote330 views1 answer
Re_path(r'^logout/$',views.logout, {"next_page":'/'},name="logout"), AttributeError: module 'django.contrib.auth.views' has no attribute 'logout'
Python
0 vote317 views1 answer
Seaborn define linewidth
Python
2 votes319 views1 answer
Test_size
Python
-1 vote351 views4 answers
Hex to string python
Python
0 vote322 views1 answer
How to get the top 100 frequent words on a python dataframe colummn
Python
4 votes316 views6 answers
Python subtract days from date
Python
0 vote322 views1 answer
Python comment header
Python
0 vote333 views1 answer
How to strip a list in python
Python
72 votes290 views6 answers
How to reverse a string in python
Python
1 vote343 views1 answer
How to check whole number in python
Python