Python list safely pop

In [1]: from typing import List, Any

In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
   ...:     try:
   ...:         return input_list.pop(index)
   ...:     except IndexError:
   ...:         return default_value
   ...:
#								list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)

In [5]: y
Out[5]: 100

# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0

Similar codes

0 vote225 views0 answer
Python
0 vote287 views1 answer
Dataframe plot conditional formatting
Python
1 vote235 views2 answers
How to sort nested list in python
Python
39 votes263 views5 answers
Dataframe create
Python
0 vote245 views1 answer
How to import a all the modules in a packege python
Python
0 vote230 views1 answer
Make a pong game in python
Python
88 votes235 views4 answers
Python os remove file
Python
0 vote250 views1 answer
Ros python service server
Python
11 votes245 views1 answer
In between in python
Python
0 vote249 views1 answer
Python read file delete first line
Python