Kable column names

require(knitr)

df <- data.frame(A=c(1,2),B=c(4,2),C=c(3,4),D=c(8,7))
knitr::kable(df, 
             col.names = c("Space in name",
                           "(Special Characters)",
                           "$\\delta{m}_1$",
                           "Space in name"))

Source: stackoverflow.com

Similar codes

0 vote258 views1 answer
Blockchain private key generator
Python
0 vote275 views1 answer
Alberi binari di ricerca python
Python
20 votes261 views1 answer
Pil get image type
Python
0 vote266 views1 answer
Python combine nested for loops
Python
3 votes387 views2 answers
Python defaultdict(list)
Python
0 vote269 views1 answer
Select default option django form
Python
16 votes288 views4 answers
Python remove last instance of a list
Python
5 votes279 views2 answers
Click button in selenium python
Python
0 vote274 views2 answers
Push button raspberry pi
Python
0 vote244 views1 answer
From flask import flask app = flask(__name__) @app.route("/") def hello_world(): return "<p>hello, world!</p>"
Python