Loc vs iloc pandas

>>> s = pd.Series(list("abcdef"), index=[49, 48, 47, 0, 1, 2]) 
49    a
48    b
47    c
0     d
1     e
2     f

>>> s.loc[0]    # value at index label 0
'd'

>>> s.iloc[0]   # value at index location 0
'a'

>>> s.loc[0:1]  # rows at index labels between 0 and 1 (inclusive)
0    d
1    e

>>> s.iloc[0:1] # rows at index location between 0 and 1 (exclusive)
49    a

Source: stackoverflow.com

Similar codes

3 votes227 views2 answers
Python initialize a 2d array
Python
0 vote231 views1 answer
Port python script to jupyter notebook
Python
0 vote219 views1 answer
Python concatenate tuple to string
Python
0 vote243 views1 answer
Return the indices of the bins
Python
0 vote249 views1 answer
Convert images to JPEG
Python
10 votes175 views1 answer
Online javascript to typescript compiler
Python
0 vote231 views1 answer
Pandas find fifth caracter in field and change cell based on that number
Python
0 vote209 views1 answer
Length of list without len function
Python
12 votes212 views2 answers
Convert list to array python
Python
4 votes201 views2 answers
How to use ternary operater in python
Python