Python sort dict by key

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sort list of dictionaries by key python

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

Python sort dict by key

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}

output:
{-1: 4, 1: 2, 4: -20}

Sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

Python dict order a dict by key

d1 = dict(sorted(d.items(), key = lambda x:x[0]))

Source: stackoverflow.com

Similar codes

38 votes378 views2 answers
Pickle.load python
Python
5 votes395 views1 answer
Get index in foreach py
Python
8 votes330 views1 answer
Python pdf to image
Python
0 vote338 views3 answers
Array of numbers
Python
0 vote359 views1 answer
Inherit functions from other classes
Python
11 votes392 views3 answers
Pd.set_option
Python
9 votes352 views2 answers
Merge 2 dataframes pythom
Python
4 votes288 views1 answer
Datetime has no attribute now
Python
0 vote378 views1 answer
Create app
Python
1 vote338 views1 answer
Python read string between two substrings
Python