/SQL/How to get the date diff on once field in sql server

How to get the date diff on once field in sql server

SELECT t1.OrderNo,DATEDIFF(day,t1.LoadedStartDate,t2.LoadedStartDate)
FROM UnnamedTableFromQuestion t1
       INNER JOIN
     UnnamedTableFromQuestion t2
       on
         t1.OrderNo = t2.OrderNo
WHERE t1.OpNo = 1 and
      t2.OpNo = 4
      
////////////////////////////////////////////////////////////////

select cur.unique_id_field, cur.seq_no, cur.date_created ,

  datediff(second, prv.date_created, cur.date_created) as diff_in_seconds

from yourtable as cur

  join yourtable as prv

    on cur.seq_no = prv.seq_no + 1;

Source: stackoverflow.com

Similar codes

5 votes225 views1 answer
Oracle sysdate - 1 month
SQL
2 votes236 views1 answer
Pdo mysql insert
SQL
0 vote227 views1 answer
Run mysql xampp shell
SQL
0 vote228 views1 answer
Change filed order in mysql
SQL
0 vote235 views1 answer
Pgadmin save data greyed out
SQL
0 vote233 views1 answer
Mysql Install Ubuntu with native password
SQL
2 votes236 views1 answer
Sql server find columns list in tables
SQL
8 votes222 views1 answer
Unique vs primary key
SQL
15 votes210 views7 answers
MYSQL
SQL
0 vote206 views1 answer
Mysql autoincrement valor inicial
SQL