/Python/Setting a condition for perfect square in python

Setting a condition for perfect square in python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Similar codes

10 votes337 views3 answers
Check python 32 or 64
Python
2 votes413 views1 answer
Auto datetime in django models
Python Django
5 votes333 views1 answer
Rolling average df
Python
0 vote327 views2 answers
I want to check my python code online
Python
0 vote323 views1 answer
Task orchestration framework
Python
0 vote365 views1 answer
Django get all model fields
Python Django
1 vote392 views1 answer
Django how to set a navbar active
Python Django
2 votes392 views3 answers
Check if value exists in list python
Python
0 vote327 views1 answer
Pyqt5 image change size
Python
0 vote365 views1 answer
Python PyDrive service account credentials
Python