/Python/How to catch stop itteration in generator as None

How to catch stop itteration in generator as None

# creating the list
L = [1,2,3,4,5,6]
# defining the generator
def generator(l):
    for i in l: yield i
    while True: yield  None
        

g = generator(L)

print(next(g)) # 1
print(next(g)) # 2
print(next(g)) # 3
print(next(g)) # 4
print(next(g)) # 5
print(next(g)) # 6
print(next(g)) # None
print(next(g)) # None
print(next(g)) # None

Similar codes

0 vote213 views1 answer
Check remote port is open or not using python
Python
-1 vote220 views1 answer
Extract specific key values from python dictionary
Python
2 votes213 views3 answers
Fibonacci formula python
Python
199 votes267 views6 answers
Pip upgrade
Python
0 vote228 views1 answer
Lcd of 18 and 21
Python
2 votes231 views1 answer
How to compare two text files in python
Python
0 vote223 views1 answer
Numpy declare arraylength
Python
2 votes225 views2 answers
Check if boolean is true python
Python
0 vote247 views1 answer
Python remove dtype from array
Python
0 vote227 views1 answer
Fibonacci numbers function python print
Python