/Python/How to catch stop itteration in generator as None

How to catch stop itteration in generator as None

# creating the list
L = [1,2,3,4,5,6]
# defining the generator
def generator(l):
    for i in l: yield i
    while True: yield  None
        

g = generator(L)

print(next(g)) # 1
print(next(g)) # 2
print(next(g)) # 3
print(next(g)) # 4
print(next(g)) # 5
print(next(g)) # 6
print(next(g)) # None
print(next(g)) # None
print(next(g)) # None

Similar codes

2 votes330 views1 answer
Python type of column
Python
5 votes341 views2 answers
If elif and else in python
Python
79 votes366 views6 answers
Python current working directory
Python
4 votes344 views5 answers
Numpy add new column
Python
0 vote357 views2 answers
Django run management command from code
Python
0 vote360 views1 answer
Mehrzeiliges kommentar python
Python
1 vote335 views1 answer
Get variance of list python
Python
8 votes352 views3 answers
Python csv add row
Python
0 vote336 views1 answer
Ad background image with tkinter
Python
-1 vote348 views1 answer
Python code to calculate encryption time
Python