R select column names starting with

#  Data
df <- data.frame( ABC_1 = runif(3),
            ABC_2 = runif(3),
            XYZ_1 = runif(3),
            XYZ_2 = runif(3) )

#      ABC_1     ABC_2     XYZ_1     XYZ_2
#1 0.3792645 0.3614199 0.9793573 0.7139381
#2 0.1313246 0.9746691 0.7276705 0.0126057
#3 0.7282680 0.6518444 0.9531389 0.9673290

#  Use grepl
df[ , grepl( "ABC" , names( df ) ) ]
#      ABC_1     ABC_2
#1 0.3792645 0.3614199
#2 0.1313246 0.9746691
#3 0.7282680 0.6518444

#  grepl returns logical vector like this which is what we use to subset columns
grepl( "ABC" , names( df ) )
#[1]  TRUE  TRUE FALSE FALSE

Source: stackoverflow.com

Similar codes

0 vote238 views1 answer
Pdlyr mutate string extract
R
0 vote257 views1 answer
Formatc in r
R
3 votes238 views3 answers
Rename columns in table r
R
0 vote232 views1 answer
How to randomly select R
R
1 vote258 views3 answers
R for loop
R
0 vote261 views1 answer
Interquartile in r
R
0 vote256 views1 answer
Histogram r add line
R
0 vote249 views1 answer
R last day of previous month
R
1 vote241 views1 answer
Replace accented characters in r
R
0 vote238 views3 answers
Cbind vectors of different lengths r
R