/Python/Take first n row of dictionary python

Take first n row of dictionary python

a_dictionary = {"name" : "John", "age" : 35, "height" : 65}

dict_items = a_dictionary.items()

first_two = list(dict_items)[:2]
print(first_two)

OUTPUT
[('name', 'John'), ('age', 35)]

first_three = list(dict_items)[:3]
print(first_three)

OUTPUT
[('name', 'John'), ('age', 35), ('height', 65)]

Similar codes

0 vote320 views1 answer
How to add a under line of the button in tkinter python
Python
12 votes327 views3 answers
Python check if input is a number
Python
5 votes333 views1 answer
Python put quotes in string
Python
5 votes341 views3 answers
Stop function python
Python
13 votes323 views6 answers
Range() python
Python
0 vote306 views1 answer
Cap.release() not working
Python
2 votes334 views1 answer
Reverse order np array
Python
0 vote306 views1 answer
Get number of zero is a row pandas
Python
2 votes408 views6 answers
What are args and kwargs in python
Python
0 vote315 views1 answer
Fibonacci 10th
Python