Django queryset group by

Django group by

# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))

# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation

#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2}, 
 {'designation': 'Manager', 'dcount': 2}]

Source: stackoverflow.com

Similar codes

3 votes429 views1 answer
Django user group check
Python Django
0 vote378 views1 answer
Q fields django Q objects
Python Django
1 vote328 views3 answers
Management commands django
Python Django
1 vote404 views2 answers
No changes detected in app django
Python Django
0 vote389 views1 answer
Django swagger settings https
Python Django
2 votes395 views2 answers
Django filter and condition
Python Django
0 vote385 views1 answer
Django never_cache example
Python Django
1 vote345 views1 answer
Django gmail smtp
Python Django
2 votes352 views1 answer
Django setup allowed hosts
Python Django
2 votes368 views1 answer
How do I mock an uploaded file in django?
Python Django