Django group by

# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))

# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation

#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2}, 
 {'designation': 'Manager', 'dcount': 2}]

Source: stackoverflow.com

Similar codes

0 vote233 views1 answer
How to instal django cities
Python Django
1 vote220 views1 answer
Use django taggit in template
Python Django
0 vote242 views1 answer
Django test postgres extensions intarray
Python Django
2 votes231 views1 answer
Django template capitalize equivalent
Python Django
1 vote234 views1 answer
Add background image in django uploaded file
Python Django
2 votes227 views1 answer
Django model current timestamp
Python Django
0 vote225 views2 answers
Django run manage.py from python
Python Django
0 vote221 views1 answer
How to add value in array django
Python Django
3 votes247 views1 answer
Access the value in settings django
Python Django
0 vote212 views1 answer
Custom auth django channels
Python Django