/Python/Python get index of first element of list that matches condition

Python get index of first element of list that matches condition

# Find first index (or value) that meets condition
my_list = [2, 4, 6, 9, 10]

# Option 1. Use an iterator (does not scan all list)
y = (i for i,x in enumerate(my_list) if is_odd(x))
idx1 = next(y)  # <== index of first element

y = (x for i,x in enumerate(my_list) if is_odd(x))
v1 = next(y)  # <== value of first element


# Option 2. Use a list comprehension (scans all list)
idx1 = [i for i,x in enumerate(my_list) if x % 2 != 0][0]
v1 = [x for i,x in enumerate(my_list) if x % 2 != 0][0]

Similar codes

0 vote129 views1 answer
Import "whitenoise.django" could not be resolved
Python Django
1 vote69 views1 answer
Install flake8 python
Python
0 vote112 views1 answer
Any and all in python3
Python
1 vote112 views1 answer
Punctuation list python
Python
0 vote100 views1 answer
Read_table python
Python
12 votes102 views2 answers
Python read from stdin
Python
0 vote107 views1 answer
Pandas add prefix to column names
Python
0 vote64 views1 answer
Divide array into equal parts/slices python
Python
19 votes118 views4 answers
How to use python to sleep if the user is not using the system
Python
0 vote105 views1 answer
Add items to list python
Python