/Python/Python get index of first element of list that matches condition

Python get index of first element of list that matches condition

# Find first index (or value) that meets condition
my_list = [2, 4, 6, 9, 10]

# Option 1. Use an iterator (does not scan all list)
y = (i for i,x in enumerate(my_list) if is_odd(x))
idx1 = next(y)  # <== index of first element

y = (x for i,x in enumerate(my_list) if is_odd(x))
v1 = next(y)  # <== value of first element


# Option 2. Use a list comprehension (scans all list)
idx1 = [i for i,x in enumerate(my_list) if x % 2 != 0][0]
v1 = [x for i,x in enumerate(my_list) if x % 2 != 0][0]

Similar codes

35 votes273 views4 answers
Get request python
Python
0 vote261 views1 answer
Deleting models with sqlalchemy orm
Python
0 vote255 views1 answer
Range endpoint
Python
3 votes272 views4 answers
Python sort multiple keys
Python
2 votes334 views3 answers
Color to black and white opencv
Python
105 votes334 views6 answers
Python json to dict
Python
0 vote276 views1 answer
Convert method to str python
Python
15 votes300 views6 answers
Value_counts() in pandas
Python
0 vote288 views1 answer
Untrack local changes
Python
0 vote288 views1 answer
Django Signup urls.py
Python