/Python/Python call function that need args with decorator

Python call function that need args with decorator

Python decorator *args **kwargs

from functools import wraps

def my_decorator(f):
    @wraps(f)
    def wrapper(*args, **kwargs):
        print('Calling decorated function')
        return f(*args, **kwargs)
    return wrapper

Python call function that need args with decorator

@decorator
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator(foo)
# So if the decorator had arguments,

@decorator_with_args(arg)
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator_with_args(arg, foo)

Similar codes

0 vote168 views1 answer
Colab tqdm import
Python
0 vote163 views1 answer
Cosh python
Python
0 vote149 views1 answer
Get token from request django
Python
5 votes167 views1 answer
Picasa
Python
0 vote182 views1 answer
Django date grater
Python Django
0 vote174 views1 answer
How to plot a linear equation in matplotlib
Python
0 vote175 views1 answer
Couldn't open showimage no such file or directory
Python
0 vote159 views1 answer
Dataframe rolling first eleemnt
Python
1 vote182 views1 answer
Create 2d list dictionary
Python
0 vote161 views1 answer
Lsit append in python
Python