/Python/Python call function that need args with decorator

Python call function that need args with decorator

Python decorator *args **kwargs

from functools import wraps

def my_decorator(f):
    @wraps(f)
    def wrapper(*args, **kwargs):
        print('Calling decorated function')
        return f(*args, **kwargs)
    return wrapper

Python call function that need args with decorator

@decorator
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator(foo)
# So if the decorator had arguments,

@decorator_with_args(arg)
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator_with_args(arg, foo)

Similar codes

0 vote257 views1 answer
What does json.loads do
Python
0 vote252 views3 answers
Seaborn heatmap x labels horizontal
Python
140 votes219 views6 answers
Python random integer in range
Python
-1 vote247 views4 answers
Hex to string python
Python
8 votes235 views1 answer
Use beautifulsoup
Python
0 vote226 views1 answer
Defaultdict count key value pairs
Python
21 votes224 views6 answers
Print statement in python
Python
5 votes265 views1 answer
How to make a module that generates a random letter in python
Python
10 votes230 views3 answers
Python print traceback from exception
Python
0 vote237 views1 answer
Discard method in python
Python