/Python/Python call function that need args with decorator

Python call function that need args with decorator

Python decorator *args **kwargs

from functools import wraps

def my_decorator(f):
    @wraps(f)
    def wrapper(*args, **kwargs):
        print('Calling decorated function')
        return f(*args, **kwargs)
    return wrapper

Python call function that need args with decorator

@decorator
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator(foo)
# So if the decorator had arguments,

@decorator_with_args(arg)
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator_with_args(arg, foo)

Similar codes

0 vote251 views1 answer
Jupyter early exit cell
Python
14 votes243 views6 answers
Print list in python
Python
0 vote270 views1 answer
Numpy sqrt
Python
0 vote243 views1 answer
Create matrix with complex python
Python
2 votes280 views1 answer
Django get current date
Python
5 votes230 views3 answers
Tuplein python
Python
3 votes243 views2 answers
Python use variable in another file
Python
0 vote241 views1 answer
Tkinter simple notification
Python
0 vote225 views1 answer
Matplotlib random color
Python
3 votes237 views1 answer
Json not readable python
Python