/Python/Invalid literal for int() with base 10 python

Invalid literal for int() with base 10 python

#another way is to check if the entered number isdigit()
#that way you will ensure unhandled exception incase of erroneus data

number= input("What is your weight:")
if number.isdigit():
    kilos=int(float(number))
    print ("The weight of the person is:" + str(kilos))
else:
    print("Error - Please enter a proper weight")

Source: itsmycode.com

Similar codes

0 vote189 views1 answer
Frequency domain parameter of speech
Python
2 votes186 views2 answers
Np logical not
Python
3 votes185 views1 answer
Pandas load txt database
Python
5 votes150 views1 answer
Python how to skip iteration
Python
1 vote160 views1 answer
Django urlpattern
Python
0 vote196 views2 answers
Pandas bins dummy
Python
4 votes166 views1 answer
Pandas find inf values
Python
0 vote164 views1 answer
.comments.all order django
Python
2 votes161 views2 answers
Sqlalchemy python install
Python
7 votes165 views1 answer
Filter dataframe multiple conditions
Python