/Python/Invalid literal for int() with base 10 python

Invalid literal for int() with base 10 python

#another way is to check if the entered number isdigit()
#that way you will ensure unhandled exception incase of erroneus data

number= input("What is your weight:")
if number.isdigit():
    kilos=int(float(number))
    print ("The weight of the person is:" + str(kilos))
else:
    print("Error - Please enter a proper weight")

Source: itsmycode.com

Similar codes

1 vote390 views1 answer
Python how often character ins tring
Python
1 vote326 views1 answer
Fill pixels with zeros python opencv
Python
-1 vote332 views1 answer
Python remove \t
Python
0 vote329 views1 answer
Numpy rolling 2d
Python
18 votes335 views2 answers
Absolute value python
Python
0 vote362 views1 answer
The requested resource was not found on this server. django
Python
0 vote329 views1 answer
Find prime in python list
Python
4 votes329 views2 answers
Display current local time in readable format
Python
0 vote351 views1 answer
Python pad with spaces
Python
2 votes327 views1 answer
Best python framework
Python