/Python/Invalid literal for int() with base 10 python

Invalid literal for int() with base 10 python

#another way is to check if the entered number isdigit()
#that way you will ensure unhandled exception incase of erroneus data

number= input("What is your weight:")
if number.isdigit():
    kilos=int(float(number))
    print ("The weight of the person is:" + str(kilos))
else:
    print("Error - Please enter a proper weight")

Source: itsmycode.com

Similar codes

0 vote250 views1 answer
Hide verbose in pip install
Python
0 vote249 views1 answer
Set environment variable flask app
Python
0 vote243 views1 answer
Dict to csv keys as rows and subkey as columns in python
Python
7 votes263 views1 answer
Float to percentage python
Python
0 vote243 views1 answer
Buttons on canvas tkinter
Python
0 vote258 views1 answer
Get page title by python bs4
Python
1 vote256 views1 answer
Pandas percentage change across 3 periods
Python
39 votes252 views6 answers
How to use a class in python
Python
0 vote233 views1 answer
Django Abstract base classe
Python
0 vote236 views1 answer
Df.rename(index=str, columns={"A": "a", "C": "c"}) what does index=str means
Python