/SQL/Comparing with today and yesterday record in sql query

Comparing with today and yesterday record in sql query

declare @bgn_dt date = '2017-12-15' --set by OP
    , @end_dt date = '2017-12-22' --set by OP
    , @lag_dt date;

set @lag_dt = (select max(MyDate) from #myTable where MyDate < @bgn_dt) --get the "yesterday" that the @bgn_dt will need

select a.MyDate
, a.SalesTotal
, format(((1.0 * a.SalesTotal) / a.SalesTotalPrevDay) - 1, '0%') as SalesTotalChange
from (
    select t.MyDate
    , t.SalesTotal
    , lag(t.SalesTotal, 1, NULL) over (/*partition by (if needed)*/ order by t.MyDate asc) as SalesTotalPrevDay
    from #myTable as t
    where 1=1
    and t.MyDate between @lag_dt and @end_dt
    ) as a
where 1=1
and a.MyDate >= @bgn_dt

Source: stackoverflow.com

Similar codes

1 vote193 views1 answer
Calculate age in sql postgresql
SQL
0 vote191 views1 answer
Get id if is not equal in certain table
SQL
0 vote184 views1 answer
Postgres select except
SQL
0 vote196 views1 answer
Pl sql round
SQL
0 vote250 views1 answer
What is metadata in sql
SQL
0 vote199 views2 answers
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'created at' in 'field list' (SQL: insert into `categories` (`category_name`, `user_id`, `created at`) values (sea fish, 1, 2021-09-24 04:17:31))
SQL
0 vote183 views1 answer
Renommer schema sql
SQL
0 vote184 views1 answer
Json_remove mysql
SQL
1 vote202 views2 answers
Sql for date greater than
SQL
0 vote208 views1 answer
Normalization in database
SQL