Php try to decode json

Php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Php try to decode json

/** Checks if JSON and returns decoded as an array, if not, returns false, 
but you can pass the second parameter true, if you need to return
a string in case it's not JSON */
function tryJsonDecode($string, $returnString = false) {
   $arr = json_decode($string);
  if (json_last_error() === JSON_ERROR_NONE) {
    return $arr;
  } else {
    return ($returnString) ? $string : false;
  }
}

Php try json decode and check

// Checks if json
function isJson($string) {
   json_decode($string);
   return json_last_error() === JSON_ERROR_NONE;
}

// example
if (isJson($string) {
  // Do your stuff here
}

-1

Similar codes

0 vote272 views1 answer
Create from format php
PHP
4 votes272 views1 answer
Disable register laravel
PHP
2 votes309 views1 answer
Laravel pivot table model
PHP Laravel
0 vote275 views1 answer
Php artisan queue start
PHP Laravel
1 vote263 views1 answer
Php shell script
PHP
0 vote305 views2 answers
How do we calculate average in laravel 8
PHP Laravel
2 votes493 views2 answers
Symfony schema update
PHP Symfony
0 vote313 views6 answers
Use varable on all site pages laravel
PHP Laravel
1 vote268 views2 answers
In array php multiple values
PHP
0 vote287 views1 answer
Php pdo sql server connect
PHP