/Java/Java scanner string nextline after nextint

Java scanner string nextline after nextint

//The problem is with the input.nextInt() method - it only reads the int value. So when you continue reading with input.nextLine() you receive the "\n" Enter key. So to skip this you have to add the input.nextLine(). Hope this should be clear now.

//Try it like that:

System.out.print("Insert a number: ");
int number = input.nextInt();
input.nextLine(); // This line you have to add (It consumes the \n character)
System.out.print("Text1: ");
String text1 = input.nextLine();
System.out.print("Text2: ");
String text2 = input.nextLine();

Source: stackoverflow.com

Sc.nextline skips

int option = input.nextInt();
input.nextLine();  // Consume newline left-over
String str1 = input.nextLine();

Source: stackoverflow.com

Similar codes

0 vote186 views3 answers
Tostring java
Java
1 vote190 views1 answer
Convert pdf to word in java
Java
3 votes192 views2 answers
Java create file in folder
Java
0 vote216 views1 answer
Javac clear
Java
1 vote207 views2 answers
Android studio keep device awake
Java
10 votes170 views4 answers
Start new activity android
Java
7 votes199 views1 answer
Java difference between array and list
Java
0 vote185 views1 answer
Spring cli version
Java
1 vote192 views1 answer
What is ioexception in java
Java
0 vote197 views1 answer
Set path in windows
Java