/Python/How to make input box if else statement in tkinter

How to make input box if else statement in tkinter

import tkinter

root = tkinter.Tk()
root.geometry("300x300")
root.title("Try code")

entry = tkinter.Entry(root)
entry.pack()
print(entry.get())
def on_button():
    if entry.get() == "Screen" or entry.get() == "screen": #corrected
        slabel = tkinter.Label(root, text="Screen was entered")
        slabel.pack()
    else:
        tlabel = tkinter.Label(root, text="")
        tlabel.pack()

button = tkinter.Button(root, text="Enter", command=on_button)
button.pack()

root.mainloop()

Source: stackoverflow.com

Similar codes

0 vote126 views1 answer
Get full detail inside of id in django rest framework many to many
Python
22 votes107 views6 answers
Python strings
Python
0 vote115 views1 answer
Write a line to a text file using the write() function
Python
0 vote130 views1 answer
Flask wtforms multiple select
Python Flask
8 votes126 views3 answers
Export multiple python pandas dataframe to single excel file
Python
2 votes114 views1 answer
Python use tqdm with concurrent futures
Python
0 vote110 views1 answer
Sql o que é
Python
58 votes98 views2 answers
Find an index of an item in a list python
Python
0 vote145 views2 answers
Requests get cookies from response
Python
0 vote118 views2 answers
Def conditional_impute(input_df, choice='median')
Python