/Python/How to make input box if else statement in tkinter

How to make input box if else statement in tkinter

import tkinter

root = tkinter.Tk()
root.geometry("300x300")
root.title("Try code")

entry = tkinter.Entry(root)
entry.pack()
print(entry.get())
def on_button():
    if entry.get() == "Screen" or entry.get() == "screen": #corrected
        slabel = tkinter.Label(root, text="Screen was entered")
        slabel.pack()
    else:
        tlabel = tkinter.Label(root, text="")
        tlabel.pack()

button = tkinter.Button(root, text="Enter", command=on_button)
button.pack()

root.mainloop()

Source: stackoverflow.com

Similar codes

5 votes311 views2 answers
Forgot django admin password
Python Django
0 vote256 views10 answers
Scrapy itemloader example
Python
3 votes269 views1 answer
How to write to a file in python without deleting all content
Python
1 vote284 views1 answer
Split list into list of lists python on every n element
Python
0 vote308 views1 answer
I want only the span of finditer in re python
Python
0 vote312 views1 answer
How to read a data file in python and build a list of files
Python
0 vote285 views1 answer
Python string match http
Python
0 vote274 views1 answer
Command run test keep db python
Python
0 vote285 views2 answers
Generate-thumbnails-in-django-with-pil
Python
1 vote291 views1 answer
How to get last values or data in django orm
Python