OpenFileDialog c#

C# open file dialog

OpenFileDialog dialog = new OpenFileDialog();
if (DialogResult.OK == dialog.ShowDialog()) 
{
    string path = dialog.FileName;
}

OpenFileDialog c#

OpenFileDialog fileDialog= new OpenFileDialog(); 
fileDialog.DefaultExt = ".txt"; // Required file extension 
fileDialog.Filter = "Text documents (.txt)|*.txt"; // Optional file extensions

fileDialog.ShowDialog();

Source: stackoverflow.com

Similar codes

0 vote219 views1 answer
Populate array from an XML file
C#
1 vote284 views1 answer
How to make an object jump in unity
C#Unity
7 votes252 views1 answer
C# absolute value
C#
1 vote243 views1 answer
C# monogame mouse position
C#
0 vote251 views1 answer
C# dapper execute stored procedure with parameters
C#
-1 vote222 views1 answer
C# declaration definition
C#
3 votes233 views1 answer
Unity get project file directory
C#Unity
0 vote194 views1 answer
Infinit range loop c#
C#
4 votes231 views1 answer
Instantiate list C#
C#
1 vote268 views1 answer
How to open any file on button click in winforms
C#