C# create dynamic json

[TestFixture]
public class DynamicJson
{
    [Test]
    public void Test()
    {
        dynamic flexible = new ExpandoObject();
        flexible.Int = 3;
        flexible.String = "hi";

        var dictionary = (IDictionary<string, object>)flexible;
        dictionary.Add("Bool", false);

        var serialized = JsonConvert.SerializeObject(dictionary); // {"Int":3,"String":"hi","Bool":false}
    }
}

Source: stackoverflow.com

Similar codes

0 vote256 views1 answer
Firepower 4125 License update
C#
1 vote276 views1 answer
Coroutine not eaffected by time.timescale unity
C#Unity
-2 votes281 views1 answer
Unity3d sort list
C#
2 votes256 views1 answer
How to make a button open window in wpf
C#
0 vote277 views1 answer
Datatable linq where clause c#
C#
0 vote237 views3 answers
How to deserialize string array in c#
C#
0 vote280 views1 answer
Cosmos db get all items in container
C#
4 votes267 views3 answers
Public gameobject
C#
32 votes366 views6 answers
Unity enable and disable gameobject
C#Unity
4 votes282 views2 answers
C# get calling method name
C#