Python perfect square

Setting a condition for perfect square in python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python perfect square

import math

def is_square(n):
    return n > -1 and math.sqrt(n) % 1 == 0


# Taking the input from user
number = int(input("Enter the Number: "))
if is_square(number):
    print(f'Your number: {number} is perfect square.')
else:
    print(f'Your number: {number} is not perfect square.')

Python num perfect squares

print(int(int(n)**.5))

Similar codes

0 vote360 views1 answer
Pe039
Python
25 votes390 views4 answers
Python is ascii
Python
0 vote419 views1 answer
Check for duplicate values in dataframe
Python
0 vote352 views4 answers
Django-sslserver · PyPI
Python
15 votes362 views4 answers
Pil resize image
Python
1 vote355 views1 answer
Django filter by date range
Python
2 votes372 views1 answer
Python apply a function on each element of a array
Python
9 votes350 views2 answers
Pygame.draw.rect()
Python
1 vote397 views1 answer
How to make an object set once python
Python
0 vote349 views1 answer
Pandas mysql error in query concat with space
Python