Python perfect square

Setting a condition for perfect square in python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python perfect square

import math

def is_square(n):
    return n > -1 and math.sqrt(n) % 1 == 0


# Taking the input from user
number = int(input("Enter the Number: "))
if is_square(number):
    print(f'Your number: {number} is perfect square.')
else:
    print(f'Your number: {number} is not perfect square.')

Python num perfect squares

print(int(int(n)**.5))

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