Python perfect square

Setting a condition for perfect square in python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python perfect square

import math

def is_square(n):
    return n > -1 and math.sqrt(n) % 1 == 0


# Taking the input from user
number = int(input("Enter the Number: "))
if is_square(number):
    print(f'Your number: {number} is perfect square.')
else:
    print(f'Your number: {number} is not perfect square.')

Python num perfect squares

print(int(int(n)**.5))

Similar codes

1 vote329 views1 answer
Serving static audio files with flask in react
Python Flask
0 vote352 views3 answers
Pandas converters example
Python
3 votes305 views1 answer
How to append to front of the list using def method in python 3
Python
0 vote300 views1 answer
Qdate to date
Python
13 votes347 views2 answers
Self calling function
Python
0 vote336 views1 answer
Seaborn heatmap spearman correlation coefficient
Python
1 vote307 views2 answers
Sin and cos in python
Python
0 vote309 views1 answer
Pyplot common labels
Python
21 votes291 views6 answers
Pygame install
Python
0 vote310 views2 answers
Django run command from code
Python Django