/C/How to check if a number is even or odd in python

How to check if a number is even or odd in python

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

Program to find even numbers in python

m = int(input("Enter number"))
if m % 2 == 0:
    print(m,"is an even number")
else:
    print(m,"is an odd number")

How to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))

Finding odd even python

number = int(input("Write a number:- "))
if number%2 == 0:
    print("Even number")
else:
    print("odd number")

Wap in python to check a number is odd or even

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
  print(num ,"is even number\n")  
#CODE BY VENOM STONE
else:  
  print(num,"is Odd number\n")
#CODE BY VENOM STONE

How to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))

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