/Python/Python get first n elements of dict

Python get first n elements of dict

Access first element of dictionary python

res = next(iter(test_dict))

Take first n row of dictionary python

a_dictionary = {"name" : "John", "age" : 35, "height" : 65}

dict_items = a_dictionary.items()

first_two = list(dict_items)[:2]
print(first_two)

OUTPUT
[('name', 'John'), ('age', 35)]

first_three = list(dict_items)[:3]
print(first_three)

OUTPUT
[('name', 'John'), ('age', 35), ('height', 65)]

Python get first n elements of dict

"""
NOTE: dictionaries do NOT remember the order in which 
key : value pairs have been stored
"""
d = {"a" : 5, "b" : 1, "c" : 8, "d" : 4, "e" : 3, "f" : 10, "g": 2}
# getting the first n key : value pairs
n = 3
first_n = dict(zip(list(d.keys())[:n], list(d.values())[:n]))
first_n
>>> {'a': 5, 'b': 1, 'c': 8}

Similar codes

0 vote348 views1 answer
How to know the number of CPu using python
Python
0 vote386 views1 answer
Get value of 1 field in model django
Python Django
0 vote334 views1 answer
Regex for repeating words python
Python
0 vote334 views1 answer
Django delete session
Python Django
1 vote340 views1 answer
Matplotlib add legend axis x
Python
0 vote329 views1 answer
Jupyter notebook don't show plot
Python
-2 votes328 views1 answer
Youtube dl python
Python
0 vote334 views1 answer
Polish notation python
Python
0 vote356 views2 answers
How to update sklearn
Python
0 vote384 views1 answer
A int and float python
Python