Sort number in dynamo

import re

liste = IN[0]

def natural_sort(l): 
    convert = lambda text: int(text) if text.isdigit() else text.lower() 
    alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ] 
    return sorted(l, key = alphanum_key)

OUT = natural_sort(liste)

Source: forum.dynamobim.com

Similar codes

0 vote238 views2 answers
== vs equals c#
C#
0 vote188 views1 answer
How to read key from web config in JavaScript
C#
0 vote234 views1 answer
Linq get a dictionary key and value c#
C#
0 vote237 views1 answer
Unity reset random seed
C#
10 votes241 views6 answers
C# string to enum
C#
28 votes238 views2 answers
How to find out if a file exists in C# / .NET?
C#
1 vote260 views1 answer
Get self component in unity
C#Unity
10 votes223 views5 answers
C# null check
C#
0 vote230 views1 answer
New material unity
C#
1 vote337 views1 answer
Unity custom editor save changes
C#Unity